(x+5)^2=x^2-5(2-x)

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Solution for (x+5)^2=x^2-5(2-x) equation: 



(x+5)^2=x^2-5(2-x)

We move all terms to the left:

(x+5)^2-(x^2-5(2-x))=0

We add all the numbers together, and all the variables

(x+5)^2-(x^2-5(-1x+2))=0



We calculate terms in parentheses: -(x^2-5(-1x+2)), so:

x^2-5(-1x+2)

We multiply parentheses

x^2+5x-10

Back to the equation:

-(x^2+5x-10)



We get rid of parentheses

-x^2+(x+5)^2-5x+10=0

We add all the numbers together, and all the variables

-1x^2-5x+(x+5)^2+10=0

We move all terms containing x to the left, all other terms to the right

-1x^2-5x+(x+5)^2=-10

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